Q 16. Coding-Decoding

If the order of the letters in the English alphabet is reversed and each letter represents the letter whose position it occupies, then which one of the following represents 'LUCKNOW'?

a) OGXPMLD
b) OGXQMLE
c) OFXPMLE
d) OFXPMLD
Answer: d
Practice This Question in Exam Mode

  •   Letter -  A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
  •   Reverse Code - Z Y X W V U T S R Q P O N M L K J I H G F E D C B A
  •   Correct code for LUCKNOW is OFXPMLD.
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Q 40. Coding-Decoding

In the English alphabet, the first 4 letters are written in opposite order, and the next 4 letters are written in opposite order and so on; and at the end Y and Z are interchanged. Which will be the fourth letter to the right of the 13th letter?

a) N
b) T
c) H
d) I
Answer: b
Practice This Question in Exam Mode

  •   English alphabats: ABCD EFGH IJKL MNOP QRST UVWX YZ
  •   As per question: DCBA HGFE LKJI PONM TSRQ XWVU ZY
  •   13th letter is P. And the 4th letter to its right is T.
Directions for the following 4 (four) items:
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Q 56. Coding-Decoding

In a code language 'MATHEMATICS' is written as 'LBSIDNZUHDR'. How is 'CHEMISTRY' written in that code language?

a) DIDLHRSSX
b) BIDNHTSSX
c) BIDLHTSSX
d) DGFLIRUQZ
Answer: b
Practice This Question in Exam Mode

The correct answer is b: BIDNHTSSX.
To solve this problem, we need to understand the pattern used to encode the word 'MATHEMATICS' into 'LBSIDNZUHDR'. Let's break it down step by step:
     ● Step 1: Analyze the Pattern  
       We need to compare each letter of 'MATHEMATICS' with 'LBSIDNZUHDR' to find the pattern or rule applied.
           ○ M -> L
           ○ A -> B
           ○ T -> S
           ○ H -> I
           ○ E -> D
           ○ M -> N
           ○ A -> Z
           ○ T -> U
           ○ I -> H
           ○ C -> D
           ○ S -> R
     ● Step 2: Identify the Transformation  
       By observing the transformation, we can see that each letter in 'MATHEMATICS' is shifted by a certain number of positions in the alphabet to get the corresponding letter in 'LBSIDNZUHDR'. Specifically:
           ○ M (13) -> L (12): Shift of -1
           ○ A (1) -> B (2): Shift of +1
           ○ T (20) -> S (19): Shift of -1
           ○ H (8) -> I (9): Shift of +1
           ○ E (5) -> D (4): Shift of -1
           ○ M (13) -> N (14): Shift of +1
           ○ A (1) -> Z (26): Shift of -1
           ○ T (20) -> U (21): Shift of +1
           ○ I (9) -> H (8): Shift of -1
           ○ C (3) -> D (4): Shift of +1
           ○ S (19) -> R (18): Shift of -1
       The pattern alternates between shifting by -1 and +1.
     ● Step 3: Apply the Pattern to 'CHEMISTRY'  
       Now, apply the same pattern to encode 'CHEMISTRY':
           ○ C (3) -> B (2): Shift of -1
           ○ H (8) -> I (9): Shift of +1
           ○ E (5) -> D (4): Shift of -1
           ○ M (13) -> N (14): Shift of +1
           ○ I (9) -> H (8): Shift of -1
           ○ S (19) -> T (20): Shift of +1
           ○ T (20) -> S (19): Shift of -1
           ○ R (18) -> S (19): Shift of +1
           ○ Y (25) -> X (24): Shift of -1
       Therefore, 'CHEMISTRY' is encoded as 'BIDNHTSSX'.
     Thus, the correct answer is b: BIDNHTSSX.
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Q 48. Coding-Decoding

The letters from A to Z are numbered from 1 to 26 respectively. If GHI = 1578 and DEF = 912, then what is ABC equal to?

a) 492
b) 468
c) 262
d) 246
Answer: d
Practice This Question in Exam Mode

When alphabets are numbered, then:

GHI = 789, DEF = 456, ABC = 123

According to the question,

GHI = 1578 = 789 × 2

DEF = 912 = 456 × 2 

ABC = 123 × 2 = 246

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Q 68. Coding-Decoding

If every alternative letter of the English alphabet from B onwards (including B) is written in lower case (small letters) and the remaining letters are capitalized, then how is the first month of the second half of the year written?

a) JuLY
b) jULy
c) july
d) JULY
Answer: d
Practice This Question in Exam Mode

  If we will write the English alphabet as described in the question we will get the 26 letters as –  AbCdEfGhIjKlMnOpQrStUvWxYz

  So, July will be written jUlY.

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Q 74. Coding-Decoding

If $ means 'divided by'; @ means 'multiplied'; # means 'minus', then the value of 10#5@1$5 is

a) 0
b) 1
c) 2
d) 9
Answer: d
Practice This Question in Exam Mode

  After changing the expression as per the conditions given in the question, we get 10#5@1$5 = 10 - 5 × 1 ÷ 5.

  Using BODMAS, we first get 1 / 5 = 1/5. Then we get 5 x 1/5 = 1. Then we get 10 – 1 = 9. Hence, we have answer 9.

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Q 21. Coding-Decoding

If LSJXVC is the code for MUMBAI, the code for DELHI is

a) CCIDD
b) CDKGH
c) CCJFG
d) CCIFE
Answer: a
Practice This Question in Exam Mode

  •   Code is a letter back for first letter, two back for second letter, three back for the third letter, and so on.
  •   So, correct code for DELHI is CCIDD.
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Q 22. Coding-Decoding

If RAMON is written as 12345 and DINESH as 675849, then HAMAM will be written as

a) 92233
b) 92323
c) 93322
d) 93232
Answer: b
Practice This Question in Exam Mode

  •   RAMON → 12345
  •   DINESH → 675849
  •   H → 9, A → 2, M → 3
  •   So HAMAM → 92323.
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Q 70. Coding-Decoding

In a certain code, '256' means 'red colour chalk', '589' means 'green colour flower' and '254' means 'white colour chalk'. The digit in the code that indicates 'white' is

a) 2
b) 4
c) 5
d) 8
Answer: b
Practice This Question in Exam Mode

  •   Since 2 is in ‘red colour chalk’, so it must mean something from this set. So 2 does not mean white.
  •   Similarly 5 is in ‘red colour chalk’ so it couldn’t mean white.
  •   Now 8 isn’t in ‘white colour chalk’ so 8 can’t mean white. So only remaining possibility is option (b).
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Q 71. Coding-Decoding

A military code writes SYSTEM as SYSMET and NEARER as AENRER. Using the same code, FRACTION can be written as:

a) CARFTION
b) FRACNOIT
c) NOITCARF
d) CARFNOIT
Answer: d
Practice This Question in Exam Mode

  •   In given code, first half of the word and second half of the word are reversed.
  •   FRACTION will be written as CARFNOIT.
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