Q 49. Problems Based on Ages

Question: What is the age of Manisha?
 1. Statement-1: Manisha is 24 years younger than her mother.
 2. Statement-2: 5 years later, the ages of Manisha and her mother will be in the ratio 3:5.
 Which one of the following is correct in respect of the Question and the Statements?

a) Statement-1 alone is sufficient to answer the Question
b) Statement-2 alone is sufficient to answer the Question
c) Both Statement-1 and Statement-2 are sufficient to answer the Question
d) Both Statement-1 and Statement-2 are not sufficient to answer the Question
Answer: c
Practice This Question in Exam Mode

Statements 1 and 2 alone are not sufficient to answer the question.

Statement 2 tells the ratio of age of Manisha and her mother 5 years later as 3:5.

Thus age of Manisha and her Mother can be expressed as 3x-5 and 5x-5

By statement 1, we get 5x – 5 = 3x – 5 + 24 or x = 12.

Thus, we can find the age of Manisha.

Thus both statements combined are sufficient to answer the question.

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Q 77. Problems Based on Ages

X said to Y, "At the time of your birth I was twice as old as you are at present." If the present age of X is 42 years, then consider the following statements:
 1. 8 years ago, the age of X was five times the age of Y.
 2. After 14 years, the age of X would be two times the age of Y.
 Which of the above statements is/are correct?

a) 1 only
b) 2 only
c) Both 1 and 2
d) Neither 1 nor 2
Answer: b
Practice This Question in Exam Mode

  •   Present age of X is 42 years. Let the present age of Y be y years.
  •   As per the question, 42 – y = 2y. So, y= 14.
  •   Eight years ago, the ages of X and Y must have been 34 and 6 respectively.
  •   We can see that the age of X was not 5 times the age of Y. Hence, this statement is incorrect.
  •   After fourteen years, the ages of X and Y will be 56 and 28 respectively.
  •   We can see that the age of X would indeed be two times the age of Y. Hence, this statement is correct.
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Q 39. Problems Based on Ages

The average age of a teacher and three students is 20 years. If all the three students are of same age and the difference between the age of the teacher and each student is 20 years, then what is the age of the teacher?

a) 25 years
b) 30 years
c) 35 years
d) 45 years
Answer: c
Practice This Question in Exam Mode

•  Let the age of each student be x years and the age of the teacher be y years.

•  According to the question,

3x + y = 20 × 4

Or 3x + y = 80 …… (1)

Also, y – x = 20 .….. (2)

By subtracting equation (1) by (2) we get:

4x = 60

Or  x = 15 years

So, y = x + 20 = 15 + 20 = 35 years

•  Hence, the age of teacher is 35 years.

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Q 18. Problems Based on Ages

In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?

a) 1992
b) 1994
c) 1996
d) 1998
Answer: b
Practice This Question in Exam Mode

•  Let Meenu’s age in 2002 be M and Meera’s age in 2002 be X.

•  In 2002, Meenu = 1/3 of Meera. => M = X/3

•  In 2010, Meenu = 1/2 of Meera. So, M + 8 = (X + 8) / 2

•  Solving these two, we get M = 8. So, in 2002, Meenu was 8 years old. So she was born in 1994.

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Q 63. Problems Based on Ages

The age of Mr. X last year was the square of a number and it would be the cube of a number next year. What is the least number of years he must wait for his age to become the cube of a number again?

a) 42
b) 38
c) 25
d) 16
Answer: b
Practice This Question in Exam Mode

  •   The age of Mr. X last year was the square of a number and it would be the cube of a number next year.
  •   Hence, we have to find two numbers, one of which is a cube and the other a square and the difference between them must be 2.
  •   Only numbers are 25 and 27 satisfy this condition.
  •   Hence, the present age of Mr. X = 26.
  •   The next time his age will be a cube of a number will be when he will become 64 years old.
  •   Hence, the least number of years he should wait = 64 – 26 = 38 years.
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Q 61. Problems Based on Ages

The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby?

a) 6 months
b) 1 year
c) 2 years
d) 2 years and 6 months
Answer: b
Practice This Question in Exam Mode

  •   The sum age of 5 peoples 3 years ago = 80
  •   Average age 3 years ago = 80/5 = 16 years
  •   Now at present age of five peoples=(3*5)+80=95
  •   Add another baby in family but average was same as ago 3 years

= (95+X)/6=16

=95+X=96, value of X=1 year(that age of baby)

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Q 16. Problems Based on Ages

A father is nine times as old as his son and the mother is eight times as old as the son. The sum of the father's and the mother's age is 51 years. What is the age of the son?

a) 7 years
b) 5 years
c) 4 years
d) 3 years
Answer: d
Practice This Question in Exam Mode

Let age of the son be x yr  Then,  father's age = 9x  And  mother's age = 8x

According to the question, 9x + 8x = 51 = 17x = 51 x = 51 = x = 51 / 17 = 3 So, the age of the son is 3 yr.  

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