The Genotype of the parent is as under: 2n + XhY x 2n + X0xh. Indicate the type of Gametes that will be formed, and character represented by their Off springs. Also indicate whether the parents are carriers or free from disorder. Find out: (i) Percentage of carriers. (ii) Percentage of Haemophilic sons and daughters. (iii) Percentage of normal off springs. (UPSC 2015, 15 Marks, )

माता-पिता का जीनोटाइप इस प्रकार है: 2n + XhY x 2n + X0xh. बनने वाले गैमीट्स के प्रकार और उनके संतानों द्वारा प्रदर्शित लक्षणों को दर्शाएं। यह भी बताएं कि माता-पिता वाहक हैं या विकार से मुक्त हैं। पता लगाएं: (i) वाहकों का प्रतिशत। (ii) हीमोफिलिक पुत्रों और पुत्रियों का प्रतिशत। (iii) सामान्य संतानों का प्रतिशत। (The Genotype of the parent is as under: 2n + XhY x 2n + X0xh. Indicate the type of Gametes that will be formed, and character represented by their Off springs. Also indicate whether the parents are carriers or free from disorder. Find out: (i) Percentage of carriers. (ii) Percentage of Haemophilic sons and daughters. (iii) Percentage of normal off springs.)
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