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CSAT 2024

Q6 2024, Fundamental Arithmetical Operation

Let's analyze the expression 5 * 4* 3* 2* 1.
We need to solve it using hit and trial method.
If we use the * symbol as subtraction (-) twice, then addition (+) and multiplication (x),
The expression = 5 - 4 - 3 + 2 x 1 = 5 – 7 + 2 = 0.
Since we want the smallest non-negative value, the correct option is (d) 0.

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